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Tricks to solve ages problem


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Hey guys .. As far as the quantitative aptitude is considered, PROBLEMS ON AGES asked in many exams.For the people who thinks logically and carries the problem has no issues with it.Actually it seems to be a easier type for them.On the otherhand,some people find it difficult to solve them and may take more time.Hence,certain tricks needs to be followed to solve them quicker and to save the time for the rest.

Trick type 1
(comparing earlier and present )   Son's age = t1 (x-1) / x-y   (comparing later and present )      Son's age = t2 (z-1) / y-z(comparing earlier and after )       Son's age = t1 (x-1) + t2 (z-1)/ x-z

where   t1 - t years earlier

t2 - t years hence

Father's age to that of son = x times (earlier/before)

Father's age to that of son = y times  ( present)

Father's age to that of son = z times   (after/hence)

PROBLEM 1
The age of a man is four times that of his son.5 yrs ago,the man was nine times as old as his son was at that time.What is the present age of the man?
SOLUTION
Son's age = t1 (x-1)/ x-y
= 5(9-1) /(9-4)  = 4x8
=32
Father's present age = 32

Trick type 2

Son's age = total ages + no of yrs ago (times -1 )  / times +1

Son's age = total ages - no of yrs after (times -1 )  / times +1


PROBLEM 2
The sum of the ages of a son and father is 56 yrs.After 4 yrs, the age of the father will be three times that of his son.What is the age of the son ?
SOLUTION
Son's age = total ages - no of yrs after (times -1 )  / times +1
 =  56 - 4( 3 - 1 ) / 3 + 1
= 48 / 4
= 12 yrs


Trick type 3
Ratio type
                            father   :   son
Present age             Y       :    X
Aftr T yrs              a         :    b


Son's age =  Y x  ( T ( a - b ) / difference of cross product )
Father's age =  X  x  ( T ( a - b ) / difference of cross product )
                           

                               father   :   son
Present age             Y       :    X
Before T yrs           a         :    b


Son's age =  Y x  ( T ( a - b ) / difference of cross product )
Father's age =  X  x  ( T ( a - b ) / difference of cross product )


PROBLEM 3
The ratio of ages of father and son at present is 6:1.After 5 yrs, the ratio will become 7 : 2. What is the present age of the son ?
SOLUTION
                             father   :   son
Present age             6        :    1
After  5 yrs             7        :    2
Son's age =  Y x  ( T ( a - b ) / difference of cross product )
   =  1 x 5( 7 - 2 ) / (6 x 2 ) - ( 7 x 1 )
   = 30 yrs


These are the main type of problems asked in competitive exams....Try to workout many problems with these easy tricks... See you soon with a new topic.
Any queries ? Comment below
Have a bright day :)






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